Selasa, 02 Mei 2017

SOAL SISTEM BERKAS PERTEMUAN 3

Fixed blocking
a)      BFR = B/R
= 2048/250
= 8,192
b)      TR    = R/T
= 250/2048
= 0,122
c)       BTT = B/T
= 2048/2048
= 1
    d)      WG = G/BFR
= 256/8,192
=31,25
   e)      WR = B/BFR
= 2048/8.192
= 250
   f)       W = WG/WR
= 31,25 + 250
=281,25
g)      T’ = (T/2)*{(R/(R+W)}
= (2048/2)*{250/(250+281,5)}
= 1024*(250/531,25)}
= 1024*0,47
= 481,28
Variable unspanned
a)      BFR = (B- R) / (R+P)
                      =(2048-) / (250+8)
= 1923/258
=7,453
   b)      W= P+( R+G) / BFR
Add caption
     = 8+(/7,453
            = 8+(381/7,453)
= 59,120
c)       T’= (T/2)* (R/ (R+W)
                                  = (2048/2)*(250/(250+59.120)
= 827,392
Variable spanned
                     a)      BFR = (B-P) / (R+P)                          
            = 2048 / 258
                           = (2048-8) / (250+8)       
 =7,90
b)      W = P+(P+G) / BFR
           = 8+(8+256) / 7,90
= 272 / 7,90
=34,40
c)       T’ = (T/2)*{R/(R+W)}
                             = (2048/2)*(250/(250+34,404)
=1024*0,879
= 900,096

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